Answer:
Hey there!
[tex]\frac{3+2-4^2(7)-5+2}{16-6(6)^2}[/tex]
[tex]\frac{3+2-16(7)-5+2}{16-6(36)}[/tex]
[tex]\frac{3+2-112-5+2}{16-216}[/tex]
[tex]\frac{-110}{-200}[/tex]
[tex]\frac{11}{20}[/tex]
Let me know if this helps :)
