Answer:
[tex]f^{-1}(x)= - \frac{1}{8} x+\frac{1}{4}[/tex]
Step-by-step explanation:
[tex]f(x) = -8x + 2[/tex]
[tex]y = -8x + 2[/tex]
[tex]y-2=-8x[/tex]
[tex]- \frac{1}{8} y+\frac{1}{4} =x[/tex]
[tex]- \frac{1}{8} x+\frac{1}{4} =y[/tex]
[tex]f^{-1}(x)= - \frac{1}{8} x+\frac{1}{4}[/tex]
