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The standard reduction potential of a chromium electrode is -0.74 volts when chromium is reduced from chromium (III). The standard potential of the cell where chromium is oxidized and cerium (IV) is reduced to cerium (III) is 2.35 V. For each half reaction how many electrons are transferred

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Answer:

three electrons were transferred in the process

Explanation:

The electrode potential of the cathode is

E°cathode= E°cell + E°anode

E°cathode = 2.35V + (-0.74V)

E°cathode= 1.61 V

Let us look at the reduction half equation; the oxidation half equation must be;

Oxidation half equation;

Cr(s) ----> Cr^3+(aq) + 3e

The reduction half equation must now be

Reduction half equation;

3Ce^4+(aq) + 3e ----> 3Ce^3+(aq)

This implies that three electrons were transferred in the process as shown by the balanced half cell reaction equations.

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