Answer:
a = 5q²
b = r²s
Step-by-step explanation:
The given identity is [tex]a^{3}-b^{3}=(a-b)(a^{2}+ab+b^{2})[/tex]
we have to use this identity to factor of two cubes given as [tex]125q^{6}-r^{6}s^{3}=(5q^{2})^{3}-(r^{2}s)^{3}[/tex]
As this expression is in the form of a³- b³
Here a is 5q² and b is r²s.
Answer:
a=5q2 b=r2s the expression factored is also (5q2-r2s) (25q4+5q2r2s+1r4s2)
Step-by-step explanation:
