Answer:
V₂ = 0.0016 m³ = 1.6 L
Explanation:
The work done by the system against a constant external pressure is given by:
W = PΔV
W = P(V₂ - V₁)
V₂ = (W/P) + V₁
where,
W = Work done by the piston = 217 J
P = Constant External Pressure = (1.5 atm)(101325 Pa/ 1 atm) = 151988 Pa
V₁ = Initial Volume = (0.15 L)(0.001 m³/1 L) = 0.00015 m³
Therefore,
V₂ = (217 J/151988 Pa) + 0.00015 m³
V₂ = 0.0016 m³ = 1.6 L
