Respuesta :

wegnerkolmp2741o

Answer:

(x-2)^2+ (y+3)^2 = 64

Step-by-step explanation:

We can write the equation of a circle as

(x-h)^2+ (y-k)^2 = r^2

Where (h,k) is the center and r is the radius

(x-2)^2+ (y- -3)^2 = 8^2

(x-2)^2+ (y+3)^2 = 8^2

(x-2)^2+ (y+3)^2 = 64

linderson92

Answer:

[tex](x-2)^2+(y-3)^2=64[/tex]

You may simplify further

Step-by-step explanation:

The eqn. of a circle with centre (h,k) and radius r is given by,

[tex](x-h)^2+(y-k)^2=r^2\\(x-2)^2+(y-3)^2=8^2\\(x-2)^2+(y-3)^2=64\\[/tex]

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