batman12272003 batman12272003

27-04-2020
Mathematics

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What are the solutions of the equation?
[tex]zx^{2} -12z+36=0[/tex]
(6,6)
(-6,6)
(-6,-6)
(6,-6)

Respuesta :

billgkgk billgkgk

27-04-2020

Answer: (6,6)

Assuming that the x is not supposed to be there, the only variable is z

Step-by-step explanation:

factor the given equation as

(z - 6)(z -6) -6×-6= +36 -6z - 6z = -12z

set each factor equal to zero to solve for z

z-6=0 z= 6

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