Answer:
169911 groups of 5 participants are possible
Step-by-step explanation:
Total no. of participants = 31
We are supposed to find no. of groups of 5 participants are possible
We will use combination over here :
Formula : [tex]^nC_r=\frac{n!}{r!(n-r)!}[/tex]
Substitute r = 5
n = 31
So,no. of groups of 5 participants are possible =[tex]^nC_r[/tex]
So,no. of groups of 5 participants are possible:
[tex]\frac{31!}{5!(31-5)!}=169911[/tex]
Hence 169911 groups of 5 participants are possible
