Answer:
given.. mass of copper 2kg
- initial temperature is copper(I)=100°c
- volume of water(5l)=5kg of water
- initial water temperature =20°c
- what's the final temperature(f)??
from the concept
heat lost from an object=heat gained by the other object
Heat=McΔT
Mč x Cč x ΔTč = Mw x Cw x ΔTw
2kg x 385J/kg°C x (100°c - {F}) = 5kg x 4200J/kg°C x ({f} - 20°C)
77000 - 770F = 21000F - 420,000
21770F =497000
....divide both sides....
F=22.83°C
therefore the final temperature of the water was 22.83°C
