Answer:
Yes. (See explanation)
Step-by-step explanation:
The procedure is described as follows:
[tex]x = \frac{132}{6}[/tex]
[tex]x = \frac{126 + 6}{6}[/tex]
[tex]x = \frac{126}{6} + \frac{6}{6}[/tex]
[tex]x = \frac{6}{6}\cdot (21+1)[/tex]
[tex]x = 1 \cdot (21+1)[/tex]
[tex]x = 21 + 1[/tex]
[tex]x = 22[/tex]
