Answer:
[tex]a=4[/tex]
Step-by-step explanation:
Given the expression
[tex]\frac{12x^2-6x}{3}=ax^2+bx+c[/tex]
Simplifying the left hand side
[tex]\dfrac{12x^2-6x}{3}=\dfrac{12x^2}{3}-\dfrac{6x}{3}=4x^2-2x[/tex]
Comparing our result with the right hand side
[tex]4x^2-2x=ax^2+bx+c\\4x^2=ax^2\\a=4[/tex]
The value of a is 4.
