Answer:
[tex]\frac{5+\sqrt{13} }{2}[/tex] , [tex]\frac{5-\sqrt{13} }{2}[/tex]
Step-by-step explanation:
For the value of y-intercepts, y = 0, because at x-axis y is 0.
We know for Ax^2 + Bx + C = 0
x = [tex]\frac{-b+\sqrt{b^{2}-4ac } }{2a}[/tex] , [tex]\frac{-b-\sqrt{b^{2}-4ac } }{2a}[/tex]
