Answer:
tangent of angle I = [tex]\sqrt{22}[/tex]/[tex]\sqrt{59}[/tex]) or [tex]\sqrt{22/59}[/tex]
Explanation:
tangent = opposite/adjacent
we need to solve for the opposite side, using pythagorean theorem
([tex]\sqrt{59}[/tex])^2 + b^2 = 9^2
59 + b^2 = 81
b^2 = 22
b = [tex]\sqrt{22}[/tex]
tangent = opposite/adjacent
tangent of angle I = [tex]\sqrt{22}[/tex]/[tex]\sqrt{59}[/tex]) or [tex]\sqrt{22/59}[/tex]
