Answer:
sin(x)=1/[tex]\sqrt10[/tex]
Step-by-step explanation:
The trigonometric identities involve trigonometric functions. Here we will be using Trigonometric identity
sin²x = 1 /( 1+cot²x )
now cot(x)= -3
⇒ cot²x= (-3)²
⇒ cot²x= 9
sin²x= 1/( 1+9)
⇒ sin²x = 1/10
taking under root on both the sides we get
√sin²x=[tex]\sqrt1[/tex]/[tex]\sqrt10[/tex]
⇒ sin(x)=± 1/[tex]\sqrt10[/tex]
