Answer:
[tex]\frac{7+\sqrt{-3} }{2} \\\\\frac{7-\sqrt{-3} }{2}[/tex]
Step-by-step explanation:
Step 1: Use the Quadratic formula to solve
[tex]x^2 - 7x = -13[/tex]
[tex]x^2 -7x+13 = -13 +13[/tex]
[tex]x^2-7x+13=0\\[/tex]
[tex]\frac{-b+\sqrt{b^2-4ac} }{2a} \\\frac{-b-\sqrt{b^2-4ac} }{2a}[/tex]
[tex]\frac{-(-7)+\sqrt{(-7)^2-4(1)(13)} }{2(1)} \\\frac{-(-7)-\sqrt{(-7)^2-4(1)(13)} }{2(1)}[/tex]
[tex]\frac{7+\sqrt{49-52} }{2} \\\\\frac{7-\sqrt{49-52} }{2}[/tex]
Answer: [tex]\frac{7+\sqrt{-3} }{2} \\\\\frac{7-\sqrt{-3} }{2}[/tex]
