Answer:
[tex]z = \frac{3n - 3}{6 - 2n}[/tex]
Step-by-step explanation:
[tex]\frac{1}{(n-1)^{\frac{1}{3} } } = (\frac{2z + 3}{4z} )^{\frac{1}{3} }[/tex]
cubing on both sides we get
[tex]\frac{1}{n-1} = \frac{2z + 3}{4z}[/tex]
4z = (2z+3)(n-1)
4z = 2nz + 3n - 2z - 3
4z - 2nz + 2z = 3n - 3
z(6 - 2n) = 3n - 3
[tex]z = \frac{3n - 3}{6 - 2n}[/tex]
