Respuesta :

Answer:

C. 6 E23 atoms Cl2

Explanation:

  • mol ≡ 6.02 E23 atoms

S.T.P:

∴ T = 25°C ≅ 298 K

∴ P = 1 atm

ideal gas:

  • PV = RTn

∴ R = 0.082 atm.L/K.mol

∴ V = 22.4 dm³ = 22.4 L

⇒ mol (n) = PV/RT

⇒ n Cl2(g) = ((1 atm)(22.4 L)/(0.082 atm.L/K.mol)(298 K))

⇒ n Cl2(g) = 0.9166 mol

⇒ atoms Cl2(g) = (0.9166 mol)*(6.022 E23 atoms/mol)

⇒ atoms Cl2(g) = 5.52 E23 atoms ≅ 6 E23 atoms

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