matevero
matevero matevero
  • 24-06-2016
  • Mathematics
contestada

HELP!!!!!! please
by substitution integrates
[tex] \int\ Sen^{3}xCosx \, dx [/tex]

Respuesta :

caylus
caylus caylus
  • 25-06-2016
Hello,

I suppose you means

As (sin(x))'=cos(x)

[tex] \int\limits{sin^3(x)*cos(x)x} \, dx [/tex]
=1/4*sin ^4(x)+C
since
[tex] \int\limits{u^3} \, du=u^4/4+C [/tex]

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