Alytucker84 Alytucker84

22-01-2020
Mathematics

contestada

Hep me ASAP!!!! A.-2 B.4 C.7-3sqrt3 D.7- sqrt3

Hep me ASAP A2 B4 C73sqrt3 D7 sqrt3 class=

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jimrgrant1 jimrgrant1

22-01-2020

Answer:

7 - 3[tex]\sqrt{3}[/tex]

Step-by-step explanation:

Given

3 + [tex]\sqrt{x+7}[/tex] - [tex]\sqrt{3x}[/tex] ← substitute x = 9

= 3 + [tex]\sqrt{16}[/tex] - [tex]\sqrt{27}[/tex]

= 3 + 4 - [tex]\sqrt{9(3)}[/tex]

= 7 - 3[tex]\sqrt{3}[/tex]

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