Answer:
No solution.
Step-by-step explanation:
[tex]3^{\sqrt{m-4} } - 3^{\sqrt{2m + 8} }=0\\3^{\sqrt{m-4} } = 3^{\sqrt{2m + 8} }, so\\\sqrt{m-4} =\sqrt{2m + 8} \\m-4=2m+8\\2m-m=-4-8\\m=-12, but\\\sqrt{-4-8} =\sqrt{-12} , that \ is \ impossible \ for \ real\ numbers.\\So,\ no\ solution.[/tex]
