Answer:
[tex]\frac{7(a-1)}{(a+2)(a-5)}[/tex]
Step-by-step explanation:
To solve this operation we need to find the common multiple of both denominators and solve for a.
[tex]\frac{3}{a+2} + \frac{4}{a-5} =\frac{3(a-5)+4(a+2)}{(a+2)(a-5)} =\frac{3a-15+4a+8}{(a+2)(a-5)} =\frac{7a-7}{(a+2)(a-5)} =\frac{7(a-1)}{(a+2)(a-5)}[/tex]
Thus, the solution is 7(a -1) / (a+2)(a-5)
