Respuesta :

Willchemistry
Molar mass :

(NH₄)₃PO₄ = 149.0 g/mol

Ca₃(PO₄)₂ = 310.17 g/mol

2 (NH₄)₃PO4 + 3 Ca(OH)₂= Ca₃(PO₄)₂ + 6 NH₄OH

2 * 149 g --------- 310.17 g
1.5 g -------------- ?

mass = 1.5 * 310.17 / 2 * 149

mass = 465.255 / 298

= 1.561 g of Ca₃(PO₄)₂

hope this helps!