Respuesta :

Answer:

C. ?????

Explanation:

Given code:

void unknown(int n)

{

if(n>0)

unkown(n-1);

System.out.print("?");  

}

Calling code: unknown(4)

This is a recursive invocation of unknown function and causes ? to be printed 5 times once each for following values of n.

  • unknown invocation with n=4
  • unknown invocation with n=3
  • unknown invocation with n=2
  • unknown invocation with n=1
  • unknown invocation with n=0

When n becomes 0, termination condition is reached and the function returns.

So the output is ?????

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