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Suppose a disk with constant angular velocity has rotational kinetic energy 1280 J. If the moment of inertia of the disk is 35 kg-m^2, then what is its angular velocity? (a) 7.604 rad/s (b) 8.552 rad/s (c) 10.12 rad/s (d) 6.818 rad/s (e) 9.952 rad/s (f) 8.935 rad/s f

Respuesta :

Answer:

Angular velocity of the disk is 8.552 rad/s

Explanation:

It is given that,

Rotational kinetic energy, KE = 1280 J

The moment of inertia of the disk, I = 35 kg m²

We have to find the angular velocity of the disk. In rotational mechanics the kinetic energy of the disk is given by :

[tex]KE=\dfrac{1}{2}I\omega^2[/tex]

[tex]\omega=\sqrt{\dfrac{2KE}{I}}[/tex]

[tex]\omega=\sqrt{\dfrac{2\times 1280\ J}{35\ kgm^2}}[/tex]

[tex]\omega=8.552\ rad/s[/tex]

Hence, the angular velocity of the disk is 8.552 rad/s.

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