Answer:
[tex]\log_{13}(169)=2[/tex]
Step-by-step explanation:
The given exponential form is:
[tex]169=13^2[/tex]
The base of the given expression on the right is 13 and the exponent is 2.
The number is 169.
In terms of logarithms, the base still remains the base and the exponent becomes the result of the logarithm of the number 169 to the given base 13.
[tex]\log_{13}(169)=2[/tex]
