Answer:
[tex]A=9\pi\ square\ units[/tex]
Step-by-step explanation:
we know that
The base of the cylinder is a circle
The area of the circle is equal to
[tex]A=\pi r^{2}[/tex]
we have
[tex]r=6/2=3\ units[/tex] ----> the radius is half the diameter
substitute
[tex]A=\pi (3)^{2}[/tex]
[tex]A=9\pi\ units^{2}[/tex]
