maddi4153 maddi4153
  • 24-05-2019
  • Mathematics
contestada

Identify the vertex and the y-intercept of the graph of the function y=-2(x+3)^2 +2.

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kamranT kamranT
  • 24-05-2019

we can simplify it to this:

[tex]y = - 2 {x}^{2} - 12x - 16 [/tex]

so we know it , the intercept in a standard equation of a parabola is C:

[tex]a {x}^{2} + bx + c[/tex]

so the intercept is (-16) and for the vertex use:

x=-b/2a

[tex]x = \frac{12}{ - 4} = - 3 [/tex]

so now put it in the equation and get the y of vertex:

y=-18+36-16=2 ==>vertex(-3,2)

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