Lyreen6355 Lyreen6355
  • 24-05-2019
  • Mathematics
contestada

Two consecutive perfect squares have a difference of $99$. what is the value of the larger perfect square?

Respuesta :

kudzordzifrancis
kudzordzifrancis kudzordzifrancis
  • 02-06-2019

Answer:

2500

Step-by-step explanation:

Let the first square number be [tex]x^2[/tex] then the next square number is [tex](x+1)^2[/tex].

The difference between these two consecutive numbers is 99.

This implies that:

[tex](x+1)^2-x^2=99[/tex]

We expand to get:

[tex]x^2+2x+1-x^2=99[/tex]

Simplify:

[tex]2x=99-1[/tex]

[tex]2x=98[/tex]

Divide both sides by 2

[tex]x=49[/tex]

Therefore the value of the larger perfect number is

[tex](49+1)^2=50^2=2500[/tex].

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