Respuesta :

[tex]\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\ \cline{1-1} r=9\\ h=13 \end{cases}\implies V=\cfrac{\pi (9)^2(13)}{3} \\\\\\ V=351\pi \implies V\approx 1102.70[/tex]

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