Answer:
The side b is 5 units
Step-by-step explanation:
Given the two sides of triangle and one angle of triangle we have to find the remaining side of triangle.
a=12 units
c=10 units
∠B=24°
we have to find the side b of triangle ABC
By cosine law,
[tex]\cos B=\frac{a^2+c^2-b^2}{2ac}[/tex]
[tex]\cos 24^{\circ}=\frac{12^2+10^2-b^2}{2(12)(10)}=\frac{144+100-b^2}{240}[/tex]
[tex]b^2=244-240\cos 24^{\circ}=24.7490901658[/tex]
[tex]b=4.97\sim 5units[/tex]
