Answer:
[tex]y+3=-\frac{1}{4}(x-8)[/tex]
Step-by-step explanation:
We want to find an equation in point-slope form of the line that passes through [tex](8,-3)[/tex] and has slope [tex]m=-\frac{1}{4}[/tex].
The point-slope form equation is given by the formula;
[tex]y-y_1=m(x-x_1)[/tex]
We substitute the given point and slope into the formula to get;
[tex]y--3=-\frac{1}{4}(x-8)[/tex]
This will simplify to
[tex]y+3=-\frac{1}{4}(x-8)[/tex]
The correct answer is C
