Answer: [tex]P(1<X<5)=0.51[/tex]
Step-by-step explanation:
Since we have given that from the table
[tex]P(X=2)=0.07\\\\P(X=3)=0.22\\\\P(X=4)=0.22[/tex]
now, we need to calculate,
[tex]P(1<X<5)\\\\=P(X=2)+P(X=3)+P(X=4)\\\\=0.07+0.22+0.22\\\\=0.51[/tex]
As we just take the values of from 2 to 4 as 1 and 5 is not included.
So, we get our answer:
[tex]P(1<X<5)=0.51[/tex]
