sydneyayanna sydneyayanna
  • 22-10-2018
  • Mathematics
contestada

Given d = 1 2 at2, solve for a. A) a = t2 2d B) a = 2d t2 C) a = d - 1 2 t2 D) a = 1 2 t2 - d

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PiaDeveau PiaDeveau
  • 31-10-2018

Given expression: [tex]d=\frac{1}{2} at^2[/tex].

We need to solve it for a.

First we need to get rid 2 from denominator.

In order to get rid 2 from denominator, we need to multiply both sides by 2.

Multiplying both sides by 2, we get

[tex]2\times d=2\times \frac{1}{2} at^2[/tex]

[tex]2d = at^2[/tex]

Now, dividing both sides by t^2, we get

[tex]\frac{2d}{a^2} = \frac{at^2}{a^2}[/tex]

[tex]a=\frac{2d}{a^2}[/tex].

Therefore, correct option is B option.

[tex]a=\frac{2d}{a^2}[/tex]

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