[tex]Let \: x \: be \: the \: length, \: y \: be \: the \: width. \\
According \: to \: the \: problem: x = 4y +4 \\
We \: have \: an \: equation: \: 2(x + y) = 478 \\ x + y = 239 \\ 4y + 4 + y = 239 \\ 5y = 235 \\ y = 47 \\ x = 4 7\times 4 + 4 = 192 \\ So \: the \: width \: is \: 47 \: and \: length \: is \: 192[/tex]
