1st even integer is x,
2d consecutive even integer is x+2,
3d consecutive even integer is x+2+2 = x+4.
Sum is x+ x+2 +x +4 = 3x + 6.
Sum is between 25 and 45, so we can write
25< 3x+6 < 45.
25 -6 < 3x < 45 -6
19 < 3x < 39
19/3 < x < 13
6 1/3 < x < 13
Between 6 1/2 and 13 there are even numbers 8,10,12 , so first even number can be 8, or 10, or 12.
1st set : 8, 10, 12
8+10+12 = 30 25<30<45
2d set: 10, 12, 14
10+12+14 =36 25<36<45
3d set : 12, 14, 16
12+14+16 = 42 25<42<45
