[tex] h(x) = x^{2} -5 [/tex]
Since x is equal to -7, substitute all the x's with -7.
[tex] h(-7) = -7^{2} -5 [/tex]
[tex] Parentheses \\ Exponents \\ Multiplication \\ Division \\ Addition \\ Subtraction [/tex]
Exponents is first:
[tex] -7^{2} = -7 \times -7 = 49 [/tex]
Your new equation is:
[tex] 49-5 [/tex]
Subtract:
[tex] 49 - 5 = 44 [/tex]
Your answer is:
[tex] h(-7) = \bf 44 [/tex]
