krisshon69 krisshon69
  • 23-08-2018
  • Mathematics
contestada

ALGEBRA 2 QUESTION SEE IF YOU CAN SOLVE!!

Solve for x.

9x+4≤58 or [tex] \frac{1}{6} [/tex]x−2>3

Respuesta :

GoddessofDork
GoddessofDork GoddessofDork
  • 23-08-2018

So starting with 9x + 4 ≤ 58, firstly subtract 4 on both sides: [tex] 9x \leq 54 [/tex]

Next, divide both sides by 9, and this inequality will be [tex] x\leq 6 [/tex]

Next with 1/6x - 2 > 3, firstly add 2 on both sides of the equation: [tex] \frac{1}{6}x>5 [/tex]

Next, multiply both sides by 6 and this inequality will be [tex] x>30 [/tex]

Putting it all together, x ≤ 6 OR x > 30.

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