We write the quadratic formula
[tex] x = \dfrac{-b \pm \sqrt{b^2 -4ac}}{2a}[/tex]
and substitute,
[tex] x= \dfrac{- -3 \pm \sqrt{(-3)^2-4(2)(-4)}}{2(2)} = \dfrac{3 \pm \sqrt{41}}{4}[/tex]
Choice C
