Respuesta :

calculista
we have
y = 3x² - 12x+10
rewrite the equation in vertex form
y-10=3x²-12x
y-10=3(x²-4x)
y-10+12=3(x²-4x+4)
y+2=3(x-2)²

is a vertical parabola open up
the vertex is a minimum 
the vertex is the point (2,-2)

therefore
the minimum value of the function is y=-2

the answer is the option 
C. -2

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