Answer:
The age of brother is 3 years .
Step-by-step explanation:
It is given that:
The age of your brother is: y years.
The age of older cousin's are:
[tex]2y^2[/tex] and [tex]6y[/tex] year old.
Also, the difference in the ages of the cousin's is zero.
This means that:
[tex]2y^2-6y=0\\\\2y(y-3)=0[/tex]
Now, as y is not equal to zero.
( since, the age of brother is older than 1 year old)
Hence, y-3=0
⇒ y=3.
Hence, the age of the brother is 3 years old.
