weberamber25 weberamber25

26-05-2018
Biology

contestada

How many moles of MgCl2 are there in 321 g of the compound?

Respuesta :

jasonD90 jasonD90

26-05-2018

MgC23= 24.31+(2 x 35.45) =95.21 g/mol

340 g Mg C12 (1 mol/ 95.21 g)= 3.57 mol MgC12

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