CodyH47 CodyH47
  • 23-05-2018
  • Mathematics
contestada

Solve for e.

9e^2f=49

e=±√7f/3

e=±7√f/3

e=±7√f/3f

e=±√7f/3f

Respuesta :

sqdancefan
sqdancefan sqdancefan
  • 23-05-2018
[tex]9e^{2}f=49[/tex]
Divide by the coefficient of e², multiply by f/f, then take the square root.
[tex]e^{2}=\dfrac{49}{9f}=\dfrac{49}{9f}\cdot \dfrac{f}{f}=\dfrac{49f}{9f^{2}}\\\\e=\pm \dfrac{\sqrt{7^{2}f}}{\sqrt{(3f)^{2}}}\\\\e=\pm \dfrac{7\sqrt{f}}{3f}[/tex]

The appropriate selection is ...
   e = ±7√f/(3f)
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stephaniep7nsa2
stephaniep7nsa2 stephaniep7nsa2
  • 11-06-2020

Answer:

e=±7√f/3f or ± [tex]\frac{7\sqrt{f} }{3f}[/tex]

Step-by-step explanation:

Verified correct with K12 test.

Answer Link

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