From the given expression:
(6x^2-54)/(5x^2-20)
simplifying the above we get:
[6(x^2-9)]/[5(x^2-4)]
=[6(x-3)(x+3)]/[5(x+2)(x-2)]
The expression will be 0 when the numerator is zero, thus given the numerator, the values that will make it 0 will be x=3 and x=-3
hence the answer is:
x=-3 and x=3
