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In the figure, the area of rectangle ABCD is 100 square
inches. Arranged as shown, points E and F are selected on
BD, so that 2(BE + FD) = 3EF. What is the area of triangle
CEF?

In the figure the area of rectangle ABCD is 100 square inches Arranged as shown points E and F are selected on BD so that 2BE FD 3EF What is the area of triang class=

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CastleRook
The area of CEF will be calculated as follows:
The ratio of (BE+FD):EF is:
3:2
But the area of BDC=1/2ABCD
thus
BDC=1/2*100=50 in
hence the area of CEF will be:
(fraction of CEF)×(Area of BDC)
fraction of CEF=2/5
hence the area will be:
2/5×50
=20 in² 

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